in reply to RFC: Is there a solution to the flaw in my hash mechanism? (And are there any others?)

I'm not sure I've captured all of the comments here, but here's my suggestion: Use the value at the hash collision to get the offset for the next hash key. If the hash value is 0 mod $PRIME, use half the prime as an offset, to avoid clustering. In Perl, if you will:

my %hash; # hash of stored values my $PRIME = some_large_prime(); # random or fixed, your choice my $PRIME_HALF = int($PRIME/2); # or some other known value or functio +n ... my $i = $initial_index; # wherever you get this from my $failed_tries = $PRIME; while (defined($hash{$i}) and $failed_tries--) { my $offset = $hash{$i} % $PRIME; $offset = $PRIME_HALF if ($offset == 0); $i = ($i + ($hash{$i}) % $PRIME; } if ($failed_tries) { $hash{$i} = $value; } else { warn "Hash full\n"; }

Update: I'm assuming that the hash values, once written, are read only, and never change.

-QM
--
Quantum Mechanics: The dreams stuff is made of

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Re^2: RFC: Is there a solution to the flaw in my hash mechanism? (And are there any others?)
by BrowserUk (Patriarch) on Jun 03, 2015 at 01:15 UTC
    Use the value at the hash collision to get the offset for the next hash key.

    Problem. The value giving the trouble is 0; so the value at the hash collision can be 0; and 0 + 0 == 0 :)

    Of course, it won't always be zero. Any multiple of the Prime size will mod to a hash of 0; but is still means that if a true 0 value arises, the thing disappears up it you know where.

    Having spent the last 3 days running some long-running, large scale simulations; I'm satisfied that the benefits of the declustering affect of the i+1 = ( i + prime ) % prime scheme are real, and outweigh the need to have an if( !i ) { //take a different path conditional test in the inner loop.

    I'm still trying a couple of things for that other path; but adding prime/2 seems as good as any other thing I've thought of.


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