Illustration of adaptation (see the parent, Re: How to remove non-numbers from string)

#! /usr/bin/perl
use 5.018;
use strict;
use warnings;

my @strings=('data.csv', 'data12.csv', '123data.csv', 'data000.csv', '
+data.csv0', '123.', '1data2.csv');

for my $string(@strings) {    
    if ( $string =~ /(\d+)/g ) {
        my $revised = $1;   
        say "\$string was:\t$string;\t RESULT: $revised (from Ln 11)";
    } else {                   # i.e., if there are no digits
        my $revised = "0";
        say "\$string was:\t$string; \t RESULT: $revised (from Ln 14)"
+;
    }
}

=head

C:\>1131407.pl
$string was:    data.csv;        RESULT: 0 (from Ln 14)
$string was:    data12.csv;      RESULT: 12 (from Ln 11)
$string was:    123data.csv;     RESULT: 123 (from Ln 11)
$string was:    data000.csv;     RESULT: 000 (from Ln 11)
$string was:    data.csv0;       RESULT: 0 (from Ln 11)     #problem1
$string was:    123.;    RESULT: 123 (from Ln 11)
$string was:    1data2.csv;      RESULT: 1 (from Ln 11)     #problem2
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• # problem1: How do you want to distingush this (or 'data0.csv') from an element with no zeros?
• # problem2: ... and what about an element with more than one set of digits, such as "1data2.csv"