in reply to Is the documentation for Perl 5.20 'pack' correct?

It looks perfectly clear to me.

If you're storing a 32 bit integer, on a little endian machine you get

[byte 1][byte 2][byte 3][byte 4] increasing memory address ->

while on a big endian machine you get

[byte 4][byte 3][byte 2][byte 1] increasing memory address ->

Obviously, big endian is superior and the only true way to store data in memory ;)