Re^3: Obtaining number of counts per each name in hash

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Re^4: Obtaining number of counts per each name in hash by Laurent_R (Canon) on Jul 07, 2015 at 20:20 UTC
I really don't see anything wrong with jeffa's answer. People who have not been exposed to hashes (or dictionaries or whatever other names they might have in other languages) often have difficulties understanding the power of these structures for many purposes (counters, removing duplicates, joins, etc.). I had the case just this week. A new hire, almost 20 years of developing experience in various languages, but no prior experience with hashes or equivalent structures. Everything else tells me that he is very probably a good developer, but I had to explain him how to use hashes to do these powerful things. OK, I found these things by myself, as far as I can remember, when I picked up Perl 11 or 12 years ago, but maybe I just was lucky enough at the time to pick up the right tutorial giving the right clues.	[reply]
Re^5: Obtaining number of counts per each name in hash by GotToBTru (Prior) on Jul 07, 2015 at 20:27 UTC
There is absolutely nothing wrong with his answer. Only a difference of opinion on pedagogy :) Dum Spiro Spero	[reply]
Re^4: Obtaining number of counts per each name in hash by gghelpneeded (Novice) on Jul 07, 2015 at 19:52 UTC
sorry if it seems that i didnt work through it.	[reply]
Re^5: Obtaining number of counts per each name in hash by GotToBTru (Prior) on Jul 07, 2015 at 20:03 UTC
There's an old adage: give a man a fish, feed him for a day. Teach him to fish, feed him forever. You owe me no apology. You can still learn from the example. If you are now more knowledgeable about Perl than you were before, that's a good day at the monastery. Dum Spiro Spero	[reply]
Re^6: Obtaining number of counts per each name in hash by Anonymous Monk on Jul 07, 2015 at 20:05 UTC
Build a man a fire, keep him warm for the night. Set that man on fire and keep him warm for his lifetime.	[reply]