in reply to What's the idea of different salts in crypt()?
If whoever doesn't know the salt, it'll take them twice as long to bruteforce the pass, and chances are, they'll never get it (the salt is half the encryption).
___crazyinsomniac_______________________________________
Disclaimer: Don't blame. It came from inside the void
perl -e "$q=$_;map({chr unpack qq;H*;,$_}split(q;;,q*H*));print;$q/$q;"
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