Re: perlrun: -a implicitly sets -n

Update: I just looked, and the first version I can find that this was introduced is in v5.20.0, here, so you probably are on v5.18.0 or earlier.

Which version of perl, and in which version of perlrun did you glean that from? I'm on v5.22.0.

steve@spek ~/scratch $ perl -wMstrict -M5.010 -ae 'say $F[0]' test.dat
foo
baz
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Re^2: perlrun: -a implicitly sets -n by 1nickt (Canon) on Jul 30, 2015 at 23:41 UTC
Thanks stevieb and browseruk, indeed, I am on 5.16.0, and the perlrun I consulted was the on-line version. I'll submit a patch with a note. The way forward always starts with a minimal test.	[reply] [d/l]
Re^3: perlrun: -a implicitly sets -n by stevieb (Canon) on Jul 30, 2015 at 23:55 UTC
Hey 1nickt, the online version (by default) is `v5.22.0`. The `v5.16.0` version doesn't have that info, so I don't know if a patch is necessary. Can you post a link to the version of `perlrun` you found this in, just to be sure?	[reply] [d/l] [select]
Re^4: perlrun: -a implicitly sets -n by 1nickt (Canon) on Jul 31, 2015 at 00:20 UTC
I was looking at perlrun. I simply prepended "Starting with Perl version 5.20 " to the existing text, hope that helps. The way forward always starts with a minimal test.	[reply] [d/l]
Re^5: perlrun: -a implicitly sets -n by stevieb (Canon) on Jul 31, 2015 at 00:50 UTC
Re^6: perlrun: -a implicitly sets -n by 1nickt (Canon) on Jul 31, 2015 at 05:06 UTC
Re^6: perlrun: -a implicitly sets -n by Anonymous Monk on Jul 31, 2015 at 07:28 UTC