danj35 has asked for the wisdom of the Perl Monks concerning the following question:
The following python code enables me to take a string of words and replace spaces with hyphens in every possible combination:
from itertools import product def dashed_combos(inputstring): words = inputstring.split() for combo in product(' -', repeat=len(words) - 1): yield ''.join(w for pair in zip(words, combo + ('',)) for w in + pair)
This will produce the following combinations from the string 'convert perl to-python'
'convert perl-to python' 'convert-perl to python' 'convert perl-to-python' 'convert-perl-to python' 'convert-perl-to-python'
I'm now trying to do exactly the same with perl. I've found a few modules that can produce the cartesian product (e.g. Math::Cartesian::Product and nested loops from Algorithm::Loops), although not being that familiar with perl I've struggled to get these to work to do what had worked so well in python. If anyone would be so kind as to help me here that would be great, as I've spent quite a while trying now, but with little joy.
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: Python to perl: itertools product to replace a char in string in each possible position
by BrowserUk (Patriarch) on Aug 10, 2015 at 08:36 UTC | |
|
Re: Python to perl: itertools product to replace a char in string in each possible position (glob)
by LanX (Saint) on Aug 10, 2015 at 11:50 UTC | |
|
Re: Python to perl: itertools product to replace a char in string in each possible position
by shmem (Chancellor) on Aug 10, 2015 at 11:24 UTC | |
|
Re: Python to perl: itertools product to replace a char in string in each possible position
by anonymized user 468275 (Curate) on Aug 10, 2015 at 10:26 UTC | |
|
Re: Python to perl: itertools product to replace a char in string in each possible position
by LanX (Saint) on Aug 10, 2015 at 11:23 UTC |