Re: Why does an array "dissolve" into a hash?

As LanX says, it’s a list assignment. So

my %h = (foo => 100,
     bar => 333,
     san => @a);
[download]

is actually

my %h = ('foo', 100, 'bar', 333, 'san', '8', 'foo', '666');
[download]

The second assignment to key foo overwrites the first, so when the assignment is complete, $h{foo} is '666'.

Hope that helps,

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Re^2: Why does an array "dissolve" into a hash? by Cody Fendant (Hermit) on Aug 20, 2015 at 03:54 UTC
Ah, that makes sense. Thank you. Is the use of the word "dissolve" normal here?	[reply]
Re^3: Why does an array "dissolve" into a hash? by ikegami (Patriarch) on Aug 20, 2015 at 13:37 UTC
"Flattened into a list" is the commonly used, though it's a bit of a misnomer. The array doesn't get flattened into another data structure; an array simply returns its elements in list context.	[reply]
Re^3: Why does an array "dissolve" into a hash? by Anonymous Monk on Aug 20, 2015 at 06:34 UTC
Never heard it used that way before.	[reply]