drusa79 has asked for the wisdom of the Perl Monks concerning the following question:
Hello, I usually work with shell script however , by requirement of one application I need a create a Perl script that calculate the password to access to the routers with a process named complement to 9, something like this: I have an IP : 10.96.3.8 1- Erase the first octet: 96.3.8 2- Complete the octets with less than 3 digits with zeros 096.003.008 3- Subtract each number to 9: 999.999.999 – 096.003.008= 903.996.991 4- Change the order to result and suppress the dots 199699309 Another exaple: The ip: 10.113.125.8 1- 113.125.8 2- 113.125.008 3- 886.874.991 4- 199478688
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Re: Calculate dynamic password by complement to 9
by Corion (Patriarch) on Nov 20, 2015 at 08:14 UTC | |
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Re: Calculate dynamic password by complement to 9
by moocow (Acolyte) on Nov 20, 2015 at 08:51 UTC | |
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Re: Calculate dynamic password by complement to 9
by Anonymous Monk on Nov 20, 2015 at 08:10 UTC | |
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Re: Calculate dynamic password by complement to 9
by Anonymous Monk on Nov 20, 2015 at 09:05 UTC |