in reply to Re^3: GetOpts not working:
in thread GetOpts not working:

I tested it and it does indeed work. How is this possible? How does it know to put the filenames into their respective places? Does it somehow auto assign a key/value pair? Im just as confused lol, because I thought you had to shift the array to get the next value, but somehow it automatically did it :0 This is what i did: 
use strict;
use warnings;

my %args = @ARGV;

print "Infile: $args{-infile}\n", "Outfile: $args{-outfile}" if ( exis
+ts $args{-infile} && exists $args{-outfile} );

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I fed it '-infile data_in.bin -outfile data_out.bin'. and it almost seems like it has assigned key/value pairs based off of my thought patterns lol <.<

I guess what i am asking is, how did it build the hash? and why did my %args = @ARGV; build it correctly like that. How is 'data_in.bin' and 'data_out.bin' not a key? if key -infile contains value 'data_in.bin' then what assigned 'data_in.bin' to be its value? there was no shifting or anything to loop through the input args

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Re^5: GetOpts not working:
by hippo (Archbishop) on Dec 10, 2015 at 16:08 UTC
    Does it somehow auto assign a key/value pair?

    Essentially, yes. When you assign directly to a hash it expects a list of key-value pairs. This is why you sometimes see the warning "Odd number of elements in hash assignment" because the list must be even-sized so that each key has a corresponding value. These two assignments are effectively the same:

    my %foo = ( baz => 1, frob => 'quux' );
my %bar = ( 'baz', 1, 'frob', 'quux' );

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    There's more about this in List value constructors in perldoc.

    Does that help?

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[d/l]
      Awesome. thanks for the link/info. i thought perl was reading my mind for a min there haha
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