in reply to Re: How to cut the directory path?
in thread How to cut the directory path?

How it can be done using regular expression?

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Re^3: How to cut the directory path?
by Laurent_R (Canon) on Feb 10, 2016 at 07:29 UTC
    If you really want to use regex, you could do this:
    my $filespec = "/usr/share/directory/piano_book.mp4"; my $relative = "." . $1 if $filespec =~ m{/usr/share(.*)};
    Or you could use split and then paste together the pieces you need.

    But you'd most probably be better off with a specialized module such as Path::Tiny mentioned above or some other.

Re^3: How to cut the directory path?
by Anonymous Monk on Feb 10, 2016 at 07:24 UTC

    How it can be done using regular expression?

    You let Path::Tiny use File::Spec which uses regular expressions for you.

Re^3: How to cut the directory path?
by AnomalousMonk (Archbishop) on Feb 10, 2016 at 18:50 UTC

    I would also advise using established modules for this, but here's another regex-only way to remove the first n directories from an absolute path. It looks like you're using a *nix path, and I haven't made the effort to define a proper directory pattern in  $dir (I don't think that any character other than a  / is allowed), so you will have to fix up the  [^/] character class accordingly.

    c:\@Work\Perl\monks>perl -wMstrict -le "my $filespec = '/usr/share/directory/piano_book.mp4'; print qq{absolute: '$filespec'}; ;; my $dir = qr{ / [^/]+ }xms; # fix [^/] ;; my $n = 2; die qq{'$filespec' could not be made relative} unless $filespec =~ s{ \A (?: $dir){$n} }{.}xms; print qq{relative: '$filespec'}; " absolute: '/usr/share/directory/piano_book.mp4' relative: './directory/piano_book.mp4'
    Please see perlre, perlretut, and perlrequick.

    Update: Added error check to substitution in example code.


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