Re: Accessing a multi-dimensional hash within an XS routine

in reply to Accessing a multi-dimensional hash within an XS routine

because

      HV* h2 = (HV*)*h2r;
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*h2r is not a hash (HV *), its a reference. You need to use SvRV to dereference it, for example:

HV *h2 = (HV *) SvRV(*h2r);
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Also, it's a good idea to check whether key1 was found (h2r != NULL) and if its a reference (SvROK(*h2r)) to a hash (SvTYPE(SvRV(*h2r)) == SVtPVHV).

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Re^2: Accessing a multi-dimensional hash within an XS routine by bh (Initiate) on Apr 03, 2016 at 21:59 UTC
Perfect! Thanks.	[reply]
Re^2: Accessing a multi-dimensional hash within an XS routine by ikegami (Patriarch) on Apr 04, 2016 at 20:18 UTC
Tip: MUTABLE_HV(...) is safer than (HV*)...	[reply]

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