Re^2: Problem with ``use if COND, Some::Module'' on Linux

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Re^3: Problem with ``use if COND, Some::Module'' on Linux by VinsWorldcom (Prior) on Apr 08, 2016 at 19:41 UTC
Not for nothing, but is 'MSWin64' an actual OS string? I'm on Windows 7 x64 with Strawberry Perl 5.22 64-bit and $^O still returns "MSWin32" for me. `VinsWorldcom@C:\Users\VinsWorldcom> ver Microsoft Windows [Version 6.1.7601] VinsWorldcom@C:\Users\VinsWorldcom> perl -v This is perl 5, version 22, subversion 1 (v5.22.1) built for MSWin32-x +64-multi-thread [...] VinsWorldcom@C:\Users\VinsWorldcom> perl -e "print $^O" MSWin32` [download]	[reply] [d/l]
Re^3: Problem with ``use if COND, Some::Module'' on Linux by stevieb (Canon) on Apr 08, 2016 at 17:45 UTC
The following works... `my $is_win = $^O =~ /MSWin/ ? 1 : 0; use if $is_win, 'Win32::Daemon'; use if ! $is_win, 'Proc::Daemon';` [download]	[reply] [d/l]
Re^4: Problem with ``use if COND, Some::Module'' on Linux by Laurent_R (Canon) on Apr 08, 2016 at 17:51 UTC
Do you really need a ternary operator here? I would think that: `my $is_win = $^O =~ /MSWin/;` [download] works the same way, doesn't it?	[reply] [d/l]
Re^5: Problem with ``use if COND, Some::Module'' on Linux by Anonymous Monk on Apr 08, 2016 at 19:30 UTC
neither version works, my $is_win is undef when "use if" is testing it at compile time	[reply]
Re^3: Problem with ``use if COND, Some::Module'' on Linux by 1nickt (Canon) on Apr 08, 2016 at 17:48 UTC
Updated to force scalar context on the pattern match output. The way forward always starts with a minimal test.	[reply]