Re: Problem with ``use if COND, Some::Module'' on Linux

Kludge, alternate, but seems that Ubuntu may ("MAY!") prefer this syntax, which works on both MSWin7 (64) and Ubuntu 14.04 and produces the expected output:

# 1159936 revising stevieb's OP

use if ( $^O !~ /MSWin/ ), 'Proc::Daemon'; 
{
  print "$INC{'Proc/Daemon.pm'}\n";
}
use if ($^O =~ /MSWin/), 'Win32::Daemon';
 {
   print "$INC{'Win32/Daemon.pm'}\n";
}
exit;
[download]

If you didn't program your executable by toggling in binary, it wasn't really programming!

Comment on Re: Problem with ``use if COND, Some::Module'' on Linux Download Code

Replies are listed 'Best First'.
Re^2: Problem with ``use if COND, Some::Module'' on Linux by 1nickt (Canon) on Apr 08, 2016 at 18:02 UTC
That doesn't fix the problem on my Ubuntu (or Darwin): `$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 14.04.3 LTS Release: 14.04 Codename: trusty` [download] Code: `use if ( $^O !~ /MSWin/ ), 'Proc::Daemon'; { print "$INC{'Proc/Daemon.pm'}\n"; } use if ($^O =~ /MSWin/), 'Win32::Daemon'; { print "$INC{'Win32/Daemon.pm'}\n"; } exit;` [download] Output: `Too few arguments to 'use if' (some code returning an empty list in li +st context?) at /home/vagrant/perl5/perlbrew/perls/perl-5.16.3/lib/5. +16.3/if.pm line 7.` [download] The way forward always starts with a minimal test.	[reply] [d/l] [select]
Re^2: Problem with ``use if COND, Some::Module'' on Linux by stevieb (Canon) on Apr 08, 2016 at 18:04 UTC
Update: I was mistaken. I didn't test both conditions... the latter one did break. Thanks ww, ~~I honestly could have sworn that I tested that, but I couldn't have, as wrapping the condition within parens does in fact work properly.~~	[reply]
Re^3: Problem with ``use if COND, Some::Module'' on Linux by 1nickt (Canon) on Apr 08, 2016 at 18:09 UTC
Really? On Ubuntu 14.04? Not for me ... The way forward always starts with a minimal test.	[reply]