Re^2: Adding an element of an array as a key for a Hash, and remaining elements as its value (would also be a hash)

Thank you Monk! That totally worked. I guess I should have tried the curly braces! Thank you very much for pointing out. This really helps!

The next question I have is how did this work and not the one I tried ? Could you please explain to me? There is something that I have to learn about these braces

Comment on Re^2: Adding an element of an array as a key for a Hash, and remaining elements as its value (would also be a hash)

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Re^3: Adding an element of an array as a key for a Hash, and remaining elements as its value (would also be a hash) by AnomalousMonk (Archbishop) on Apr 12, 2016 at 02:37 UTC
... something that I have to learn about these braces `$MasterHash{$mvr} = { map { split /:/; } @array1 };` `^ ^ ^ ^` `\| \| \| \|` `\| + sub block + \|` `\| \|` `+ anon hash ref constructor +` See perlref for anonymous reference constructors (in particular, Making References section 3 for the anon hash ref constructor) and also perlreftut. See map for the function of the sub(routine) block. Give a man a fish: `<%-{-{-{-<`	[reply] [d/l] [select]
Re^4: Adding an element of an array as a key for a Hash, and remaining elements as its value (would also be a hash) by abhiram10 (Initiate) on Apr 12, 2016 at 03:21 UTC
Thank you very much AnomalousMonk. I will do some reading and understand deeper. This is very useful. I appreciate your time and efforts to explain it to me!	[reply]
Re^3: Adding an element of an array as a key for a Hash, and remaining elements as its value (would also be a hash) by Anonymous Monk on Apr 12, 2016 at 02:44 UTC
also map in scalar context produces a count of the number of elements instead of the list of elements	[reply]