in reply to Passing regex result into function

Try: 
my $str = 'abc';
my ($arg) = $str =~ /b/i;
PassRegex($arg, 'parm2', 'parm3');

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Regex matches behave differently depending if they are in a list or scalar context.

Update: And to more specifically answer your question, no match returns undef

.

Update 2: You could also do something like this: 

PassRegex($str =~ /b/i || 0, 'parm2', 'parm3');

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Re^2: Passing regex result into function
by AnomalousMonk (Archbishop) on Apr 16, 2016 at 00:24 UTC

    The  m// operator returns false (the empty string), not undef, on match failure when evaluated in scalar context: 

    c:\@Work\Perl\monks>perl -wMstrict -le
"my $str = 'abc';
 PassRegex(scalar($str =~ /x/i), 'parm2', 'parm3');
 ;;
 use Data::Dumper;
 ;;
 sub PassRegex {
   print Dumper(\@_);
   print qq{BoolExpr = '$_[0]'  parm2 = '$_[1]'  parm3 = '$_[2]'};
   return;
   }
"
$VAR1 = [
          '',
          'parm2',
          'parm3'
        ];

BoolExpr = ''  parm2 = 'parm2'  parm3 = 'parm3'

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    Please see Regexp Quote-Like Operators.

    Give a man a fish:  <%-{-{-{-<

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Re^2: Passing regex result into function
by sdsommer (Initiate) on Apr 15, 2016 at 20:49 UTC

    Thank You! That answers my question. Next time I'll remember to check the documentation first.

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