Re: Fibonacci numbers

Well i've tried this but is not giving the desired result...

$a=1;
$b=1;
$c=$a+$b;

while($a <=100){
     print("$a\n");
     print("$b\n");
     print("$c\n");
     $a=$b+$c;
     $b=$a+$c;
    }
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Re: Re: Fibonacci numbers by claree0 (Hermit) on Oct 02, 2001 at 14:40 UTC
OK, if you're going to make an attempt at it, then we can help Lets see....at the start you set $a and $b to 1, and $c to $a+$b = 2 Then, on each iteration round the loop, you print out all three variables, then add 2 ($c from your initialisation) to $a and $b, then repeat. The assignment of $c=$a+$b simply sets $c according to the values of $a and $b at the time of assignment, and does not 'recalculate' on each trip around the loop. You will also have to rethink the calculation, as it doesn't quite work. p.s. try using strict and warnings.	[reply]

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Re: Re: Fibonacci numbers
by claree0 (Hermit) on Oct 02, 2001 at 14:40 UTC

OK, if you're going to make an attempt at it, then we can help

Lets see....at the start you set $a and $b to 1, and $c to $a+$b = 2

Then, on each iteration round the loop, you print out all three variables, then add 2 ($c from your initialisation) to $a and $b, then repeat.

The assignment of $c=$a+$b simply sets $c according to the values of $a and $b at the time of assignment, and does not 'recalculate' on each trip around the loop.

You will also have to rethink the calculation, as it doesn't quite work.

p.s. try using strict and warnings.

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