in reply to pattern matching -- feeling stoopit
This looks like homework but....
m/(pl)/ will store a value in $1, m/pl/ won't. It's the brackets that define what gets written to $n
$japh->{'Caillte'} = $me;
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Re: Re: pattern matching -- feeling stoopit
by Anonymous Monk on Oct 02, 2001 at 20:43 UTC |