Re^2: preserving hash value outside the loop

Actually I have multiple files as in the example and I want to get the output as shown in output.txt.

1.txt

@gi
AGAT
+
AAAA    1:1.txt

@gi
CATT
+
AAAAA    3:1.txt
[download]

2.txt

@gi
AGAT
+
AAAA    1:2.txt

@gi
TACA
+
AAAA    2:2.txt
[download]


output.txt

@gi
AGAT
+
AAAA    2    1:1.txt    1:2.txt
@gi
CATT
+
AAAAA    3    3:1.txt
@gi
TACA
+
AAAA    2    2:2.txt
[download]

my code is:

#!/usr/bin/env perl
use strict;
use warnings;

my %compare;

$/="";
my $key;
my $value;

while (<>) {
chomp;
   ( $key, $value ) = split('\t', $_);
   
   my @lines = split /\n/, $key;
   my $key1 = $lines[1];
   
    
    push( @{ $compare{$key1} }, $value );
 

}


foreach my $key1 ( sort keys %compare ) {

my $tot = 0;
my $file_count = @ARGV;

for my $val ( @{$compare{$key1}} ) {
        $tot += ( split /:/, $val )[0];
    }   
    
if ( @{ $compare{$key1} } >= $file_count) {


        print join( "\t", $key, $tot, @{ $compare{$key1} } ), "\n\n";
    }
}
[download]

This gives me the count correct but $key is the last variable set. How can I print each value of $key with the total count and @{ $compare{$key1} }. I am new to perl so such a question. sorry if it sounds stupid.

Comment on Re^2: preserving hash value outside the loop Select or Download Code

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Re^3: preserving hash value outside the loop -- silly oneliner by Discipulus (Canon) on May 11, 2016 at 12:27 UTC
The question sound familiar to me... # warning windows doublequotes perl -lne "BEGIN{$/=''} @arr = split /\s+/,$_;$key=join qq(\n),@arr[0 +..3]; push @{$hash{$key}},$arr[4]; $arr[4]=~/(\d+):/? $count{$key}+= +$1:'';END{print map {qq($_ $count{$_} @{$hash{$_}} \n\n)} keys %hash + }" gen1.txt gen2.txt @gi AGAT + AAAA 2 1:1.txt 1:2.txt @gi CATT + AAAAA 3 3:1.txt @gi TACA + AAAA 2 2:2.txt perl -MO=Deparse -lne "BEGIN{$/=''} @arr = split /\s+/,$_;$key=join q +q(\n),@arr[0..3]; push @{$hash{$key}},$arr[4]; $arr[4]=~/(\d+):/? $c +ount{$key}+=$1:'';END{print map {qq($_ $count{$_} @{$hash{$_}} \n\n) +} keys %hash }" gen1.txt gen2.txt BEGIN { $/ = ""; $\ = "\n"; } LINE: while (defined($_ = <ARGV>)) { chomp $_; sub BEGIN { $/ = ''; } @arr = split(/\s+/, $_, 0); $key = join("\n", @arr[0..3]); push @{$hash{$key};}, $arr[4]; $arr[4] =~ /(\d+):/ ? $count{$key} += $1 : '???'; sub END { print map({"$_ $count{$_} @{$hash{$_};} \n\n";} keys %hash); } ; } -e syntax OK [download] UPDATE still silly but no need of a separate hash to hold the count and no need of an array to accumulate the strings. + #fix missed { in {c} perl -lne "BEGIN{$/=''}@ar=split /\s+/,$_;$k=join qq(\n),@ar[0..3];$h +{$k}{s}.=' '. $ar[4];$h{$k}{c}+=$1 if $ar[4]=~/(\d+)/;END{print map{q +q($_ $h{$_}{c} $h{$_}{s}\n\n)} keys %h}" gen1.txt gen2.txt @gi AGAT + AAAA 2 1:1.txt 1:2.txt @gi CATT + AAAAA 3 3:1.txt @gi TACA + AAAA 2 2:2.txt # infact the dumped datastructure is easily intellegible: # in the oneliner h is for hash # s is for string # c for count (ah! never use single char variable names!) perl -MData::Dump -lne "BEGIN{$/=''}@ar=split /\s+/,$_;$k=join qq(\n), +@ar[0..3];$h{$k}{s}.=' '.$ar[4];$h{$k}{c}+=$1 if $ar[4]=~/(\d+)/;END{ +dd %h}" gen1.txt gen2.txt ( "\@gi\nAGAT\n+\nAAAA", { c => 2, s => " 1:1.txt 1:2.txt" }, "\@gi\nCATT\n+\nAAAAA", { c => 3, s => " 3:1.txt" }, "\@gi\nTACA\n+\nAAAA", { c => 2, s => " 2:2.txt" }, ) #oh well we dont need @ar at all, perl -a at the rescue: perl -lane "BEGIN{$/=''}$k=join qq(\n),@F[0..3];$h{$k}{s}.=' '.$F[4]; +$h{$k}{c}+=$1 if $F[4]=~/(\d+):/;END{print map{qq($_ $h{$_}{c} $h{$_} +{s}\n\n)} keys %h}" gen1.txt gen2.txt # ok i've nothing better to do this night.. perl -lane "BEGIN{$/=''}map{$h{$_}{s}.=' '.$F[4];$h{$_}{c}+=$1 if $F[ +4]=~/(\d+):/}join qq(\n),@F[0..3]; END{print map{qq($_ $h{$_}{c} $h{$ +_}{s}\n\n)} keys %h}" gen1.txt gen2.txt [download] L* There are no rules, there are no thumbs.. Reinvent the wheel, then learn The Wheel; may be one day you reinvent one of THE WHEELS.	[reply] [d/l] [select]
Re^4: preserving hash value outside the loop -- silly oneliner by Anonymous Monk on May 17, 2016 at 05:29 UTC
Thank you everyone but the above codes not giving correct output. It is giving the count correct but $key is printing the same value everytime.	[reply]
Re^5: preserving hash value outside the loop -- silly oneliner by Discipulus (Canon) on May 17, 2016 at 07:07 UTC
which code is giving you always the same key? it seems not probable to me. In case post your code , your data and your output. Here mines: `#cat gen1.txt @gi AGAT + AAAA 1:1.txt @gi CATT + AAAAA 3:1.txt #cat gen2.txt @gi AGAT + AAAA 1:2.txt @gi TACA + AAAA 2:2.txt perl -lane "BEGIN{$/=''}map{$h{$_}{s}.=' '.$F[4];$h{$_}{c}+=$1 if $F[ +4]=~/(\d+):/}join qq(\n),@F[0..3]; END{print map{qq($_ $h{$_}{c} $h{$_}{s}\n\n)} keys %h}" + gen1.txt gen2.txt @gi AGAT + AAAA 2 1:1.txt 1:2.txt @gi CATT + AAAAA 3 3:1.txt @gi TACA + AAAA 2 2:2.txt` [download] L* There are no rules, there are no thumbs.. Reinvent the wheel, then learn The Wheel; may be one day you reinvent one of THE WHEELS.	[reply] [d/l]