Re: Match only last occurrence

/text: \d{3}.*?$/sa;

Update: See tye's important observation and correction in the reply. You could instead anchor the regex at the start to have it match the last. eg:

/^.*text: \d{3}/sa;
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Re^2: Match only last occurrence (left-most then longest) by tye (Sage) on May 31, 2016 at 14:46 UTC
Actually, that doesn't work. The regex engine finds the first match of "text: \d{3}" and then tries to match ".?" anti-greedily but still matches .? before it would backtrack and try matching the second match. Anti-greediness doesn't trump "left-most first". It only trumps "longest first". I think the simplest approach is: `my $match = ( /text: ([0-9]{3})/g )[-1];` [download] But if you want to have the regex enforce the "last" part, then you have to get more complicated: `my( $match ) = /text: ([0-9]{3})(?:(?!text: [0-9]{3}).)*$/s;` [download] - tye	[reply] [d/l] [select]
Re^3: Match only last occurrence (left-most then longest) by sotona (Scribe) on May 31, 2016 at 14:52 UTC
That's it! I didn't figure out I have to repeat the pattern to match exactly the last occurrence. Thanks a lot! Sapienti sat.	[reply]
Re^3: Match only last occurrence (left-most then longest) by hippo (Archbishop) on May 31, 2016 at 15:08 UTC
Anti-greediness doesn't trump "left-most first". It only trumps "longest first". How right you are - thanks for the spot and the correction.	[reply]
Re^2: Match only last occurrence by sotona (Scribe) on May 31, 2016 at 14:47 UTC
matches the first occurence Sapienti sat.	[reply]