in reply to Quoting each word in an arrayref

Why do you use join(', ', ... when you don't want a string?

Most JSON modules know how to deal with an arrayref, so construct the arrayref directly:

$return->{$w} = [map { $_->[0] } @$rows];

Replies are listed 'Best First'.
Re^2: Quoting each word in an arrayref
by soundX (Acolyte) on Jul 22, 2016 at 09:51 UTC
    Thank you, that worked perfectly.

    @hippo. Thank you also. I am using a JSON module to encode the response but doing so gives me the data in this format [["val1"],["val2"]] which is why I was using map to get ["val1", "val2"]. Is there a better way to do this?

      Hi soundX,

      Is there a better way to do this?

      That depends, personally I like the map solution, but if your data structure is more complicated than the small example you've shown then perhaps there is an even better solution. Note that the solution given by Corion, based on your code, only pulls the first value out of the nested array, if the nested arrays have a different number of values in them then another approach might be more appropriate. Here are some variations to play around with (JSON output manually sorted):

      use warnings; use strict; use JSON::MaybeXS; my $rows = [["val1"],["val2"]]; my $rows_a = [[],["val2","val3"]]; my $return; $return->{'key1'} = [join(', ', map { $_->[0] } @$rows)]; $return->{'key2'} = [map { $_->[0] } @$rows]; $return->{'key3'} = [map { @$_ } @$rows]; $return->{'key2_a'} = [map { $_->[0] } @$rows_a]; $return->{'key3_a'} = [map { @$_ } @$rows_a]; print encode_json($return), "\n"; __END__ { "key1":["val1, val2"], "key2":["val1","val2"], "key3":["val1","val2"], "key2_a":[null,"val2"], "key3_a":["val2","val3"] }

      Hope this helps,
      -- Hauke D