Re: Counting ID on the basis of batch

#!/usr/bin/perl -l

# http://perlmonks.org/?node_id=1172420

use strict;
use warnings;

my %counter;

while(<DATA>)
  {
  chomp;
  my @parts = split /\|/;
  $counter{ join ' ', @parts[0, 4, 1] }++;
  }

for (sort keys %counter)
  {
  my @parts = split;
  print join '|', @parts[0, 1], $counter{$_}, $parts[2];
  }

__DATA__
CC225|Rosha|xyz|2221|b1
CC225|Rosha|xyz|2230|b1
CC225|Rosha|xyz|2221|b1
CC225|Rosha|xyz|2221|b1
CC225|Roshw|xyz|2222|b2
CC225|Roshw|xyz|2230|b2
CC222|Roqsha|xyz|2222|b1
CC222|Roqsha|xyz|2244|b1
CC222|Roqsh|xyz|2221|b2
CC222|Roqsh|xyz|2111|b2
[download]

Comment on Re: Counting ID on the basis of batch Download Code

Replies are listed 'Best First'.
Re^2: Counting ID on the basis of batch -- oneliner by Discipulus (Canon) on Sep 23, 2016 at 20:07 UTC
eh no! uneasy question uneasy answer! `# warning win32 doublequotes perl -F"\W" -lanE "$r{join('\|',@F[0,4,1])}++}{say s/(\\|\w+$)/\\|$r{$_}$ +1/r for keys %r" data.txt` [download] L* There are no rules, there are no thumbs.. Reinvent the wheel, then learn The Wheel; may be one day you reinvent one of THE WHEELS.	[reply] [d/l]