Re: printf rounding issue

That's a classic, see for instance perl floating number addition and following discussion.

In short, the internal representation of numbers is in binary system, which can't do all decimal fractions without rounding error.

Cheers Rolf
_{(addicted to the Perl Programming Language and ☆☆☆☆ :)

Je suis Charlie!}

Comment on Re: printf rounding issue

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Re^2: printf rounding issue by vishy_acts (Novice) on Nov 16, 2016 at 13:54 UTC
I am doing same thing as mentioned in the thread . `$val = $val * 100 ; $val = $val / 100;` [download] This is the reason I am getting correct value when I am printing on screen with print . My issue is why I am getting different values when I am using print and printf . Also what is the solution to print value correctly in FILE .	[reply] [d/l]
Re^3: printf rounding issue by LanX (Saint) on Nov 16, 2016 at 14:07 UTC
> I am doing same thing as mentioned in the thread . `$val = $val * 100 ; $val = $val / 100;` [download] from the thread: The shift must be a string operation. Dividing by 100 reintroduces the problem with floats! edit > My issue is why I am getting different values when I am using print and printf as Eily already told you, you are rounding in `printf` at the second position not the third. Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :) Je suis Charlie!}	[reply] [d/l]