Hi opaltoot,

See Assignment Operators:

... the scalar assignment operator produces a valid lvalue. Modifying an assignment is equivalent to doing the assignment and then modifying the variable that was assigned to. This is useful for modifying a copy of something, like this:

($tmp = $global) =~ tr/13579/24680/;
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... Likewise,

($x += 2) *= 3;
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is equivalent to

$x += 2;
$x *= 3;
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Hope this helps,
-- Hauke D

thanks, yes that helps

In the same way that

print $a = 2, ' ', $a = 3, "\n";
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prints

3 3
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:)

This is because the entire expression is evaluated before being passed as arguments to print. print doesn't get called iteratively for each argument. It gets its arguments, and then iterates.

So that means $a = 2 is evaluated, then ' ', then $a = 3, and then the values of $a, ' ', and $a are passed to print. By the time the expression has been evaluated, $a contains 3 no matter how many times it appears in @_.




Dave