Re^7: Interpolating data using pdl

zeroes(21600,10800) works for me. Are you on 32-bit OS? Then use 64-bit. If your data is going to finish as 8 bits per channel image anyway, then work with byte piddles.

P.S. BTW, you understand, that your image will be 700 MB (uncompressed), don't you?

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Re^8: Interpolating data using pdl by etj (Priest) on May 10, 2022 at 15:23 UTC
PDL 2.067 removed the `$PDL::BIGPDL` check, because 1GB isn't big anymore. `zeroes(21600,10800)` has about 200,000 elements in, which for `double` (the default) at 8 bytes each would be about 1.6GB. `float` would be half that. `byte` would naturally be an eighth. Which to use depends on both available resources, and the needs of your application.	[reply] [d/l] [select]