Re: How to take only maximum directory name by using its digits using perl?

Re-read the file and print out things that have the right rev?

seek LOGFILE, 0, 0;
while (<LOGFILE>) {
   if (/rev_(\d+)/) { print if $1 == $max_id }
}
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Comment on Re: How to take only maximum directory name by using its digits using perl? Download Code

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Re^2: How to take only maximum directory name by using its digits using perl? by finddata (Sexton) on Mar 29, 2017 at 05:50 UTC
By the above i couldnt see any changes with my output.The same it prints	[reply]
Re^3: How to take only maximum directory name by using its digits using perl? by Anonymous Monk on Mar 29, 2017 at 06:10 UTC
I'm guessing that you've replaced part of your code with the code I posted. You're meant to add my code after yours. It's very difficult to give useful answers when you keep making us guess what you're really doing.	[reply]