in reply to Re^2: How do you match a stretch of at least N characters
in thread How do you match a stretch of at least N characters

No, it's a replacement. It reports 107 matches for me, 92 of them are exact.

($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord }map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,

Replies are listed 'Best First'.
Re^4: How do you match a stretch of at least N characters
by Anonymous Monk on Sep 11, 2017 at 14:52 UTC
    Aha, ok, I see, probably I just ran into the exact ones by chance... I know I am pushing my luck a bit, but since you have been so helpful and the code is yours, is there a way that I can see which of the 10-mers are consecutive and "paste" them into one larger match?
    AGCAATATTTCAAG AGCAATATTTCAAG GCAATATTTCAAGA GCAATATTTCAAGA

    For example, these 2 are basically the same, just going 1 position further.
    Hm, now that I am thinking it better, was the problem I asked for a question of finding the longest possible match with one mismatch allowed? Would that have been easier and I was wasting everyone's time here?
      > is there a way that I can see which of the 10-mers are consecutive and "paste" them into one larger match?

      It's not so easy. You can't paste them together, as that might increase the number of mismatches over the threshold.

      But you can change the algorithm totally if you want to find the longest matches. Just move the shorter string alongside the longer one, and then for each position try to find the longest match starting there.

      #!/usr/bin/perl use warnings; use strict; use feature qw{ say }; my $stretch = 10; my $mismatches = 1; substr $reference_str, 0, 0, 'x' x (length($small_str) - 1); $reference_str .= 'x' x (length($small_str) - 1); for my $start_pos (0 .. length($reference_str) - length($small_str)) { my $substr = substr $reference_str, $start_pos, length($small_str) +; my ($from, $diffs) = (0, 0); for my $inner_pos (0 .. length($small_str) ) { ++$diffs if substr($substr, $inner_pos, 1) ne substr $small_str, $inner_pos, 1; if ($diffs > $mismatches || $inner_pos == length($small_str) ) + { say join "\n\t", $start_pos + $from + 1 - length $small_str, substr($small_str, $from, $inner_pos - $from), substr($reference_str, $from + $start_pos, $inner_pos +- $from) if $inner_pos - $from >= $stretch; ++$from until (substr $small_str, $from, 1) ne substr($sub +str, $from, 1) || $from > $inner_pos; ++$from; --$diffs; } } }

      > was the problem I asked for a question of finding the longest possible match with one mismatch allowed?

      Basically, yes.

      ($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord }map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,
        I think it does what I needed!
        I will now study the code you kindly provided, thank you very much!