Re: Small Perl 6 discoveries III, Ints

The exponential notation always produces a Num (and therefore introduces rounding errors), even when a value could be expressed as a Rat. This is by design as I have been told. It works correctly though if you do this:

> 2*(10**25)
20000000000000000000000000
> 20*(10**24)
20000000000000000000000000
> 2*(10**25) == 20*(10**24)
True
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holli

You can lead your users to water, but alas, you cannot drown them.

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Re^2: Small Perl 6 discoveries III, Ints by Anonymous Monk on Sep 29, 2017 at 05:56 UTC
Yes, thanks. We've discovered that the Int is actually working correctly in this case, but the Num is broken.	[reply]
Re^3: Small Perl 6 discoveries III, Ints by holli (Abbot) on Sep 29, 2017 at 06:04 UTC
It's not broken. It's just a floating point number. holli You can lead your users to water, but alas, you cannot drown them.	[reply] [d/l]
Re^4: Small Perl 6 discoveries III, Ints by Anonymous Monk on Sep 29, 2017 at 06:08 UTC
If you take the simplistic point of view that "floating point numbers just give the wrong answer sometimes," you might come to that conclusion. But floating point numbers actually follow very specific rules, which are being broken here.	[reply]