Re: list two paths files into one array

As a preliminary note, I would say that your code doesn't compile. Even the very first line doesn't compile.

Otherwise, what you can do is to store the entries of the first dir into an array, and then add the entries of the second one to this array. Something like this:

my $Dir1 = "d:/xxxxxx";
my $Dir2 = "d:/yyyyyy";
my @files = glob ("$Dir1/*");
for my $file (glob "$Dir2/*" ) {
    push @files, $file;
}
for my $file (@file) {
    print $file, "\n"
}
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Of course, this can be made somewhat shorter:

my $Dir1 = "d:/xxxxxx";
my $Dir2 = "d:/yyyyyy";
my @files = glob ("$Dir1/*");
push @files, $_ for glob "$Dir2/*";
print $_, "\n" for @file;
[download]

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Re^2: list two paths files into one array by pryrt (Abbot) on Nov 14, 2017 at 00:54 UTC
push accepts a list as the second "argument" (and provides list context in that position), so there's no need for the `for` loop around the second glob: `push @files, glob "$Dir2/*";` is sufficient. Of course, now we've given the spoiler for my step #3... oh, well.	[reply] [d/l] [select]
Re^3: list two paths files into one array by Laurent_R (Canon) on Nov 14, 2017 at 08:28 UTC
Yes, this is right: there is no real need for the `for` loop in this case. I thought that it was still better to show the process in an explicit loop since the OP is really a beginner. TIMTOWTDI, there are in fact many ways to do it. Sorry for "spoiling" your answer, I did not think about that, but just thought that the OP deserved a simple example solution.	[reply] [d/l]