Another point is that I don't see any reason to print incremental results each time through the look (except possibly for debugging purposes). Put the print statement after the end of the foreach loop.

And you might want to use printf instead of print in this specific case. In fact, using printf might be the only change that you need in your original code, as shown with this example under the Perl debugger:

  DB<1> @nr=('32431.19', '20', '-10', '-31800');

  DB<2> $x=0;

  DB<3> $x += $_ for  @nr;

  DB<4> print $x
641.189999999999
  DB<5> printf '%.2f', $x;
641.19
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The numbers have maximum 2 digits. The code is just for debugging, extracting the problem from a larger code, to have some small code to play. In the original code all sums are stored in an array and used later. Therefore printf is only a solution for the small debug code.

You need the round. The effect is much more seldom when using *100, but still exists. Please see:

my @nr=('34455.28','-33907.55');
my $x=0;
foreach (@nr)
{ $x+=($_*100);
  print "$_ => ".$x/100 ."\n";  
}

34455.28 => 34455.28
-33907.55 => 547.729999999995
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Yes, I wrote my message too quickly, you're right that some form of rounding is needed if you want to make sure to use integer addition; multiplying the numbers by 100 is not always sufficient to get proper integers.

Having said that, I still think that using just printf (or sprintf to convert the results and store them in an array) on the final result is probably sufficient to get the right precision (unless you're really adding huge volumes of numbers).