in reply to Re: Using constants as hash keys
in thread Using constants as hash keys
Hello karlgoethebier,
I’ve been a fan of Const::Fast since I discovered it recently in the Perl Advent Calendar 2017. But constant does have one important advantage over Const::Fast: it is applied at compile time, whereas Const::Fast takes effect only at run time. So, in this respect, Const::Fast suffers from the same limitation, identified by choroba, as the &CONSTANT syntax for the constant pragma — the constant isn’t inlined:
0:59 >perl -Mstrict -MData::Dump -MConst::Fast -we "use constant A => + 12; const our $B => 13; my %h = ( (A) => 'twelve', $B => 'thirteen') +; dd \%h;" { 12 => "twelve", 13 => "thirteen" } 0:59 >perl -Mstrict -MO=Deparse -MData::Dump -MConst::Fast -we "use c +onstant A => 12; const our $B => 13; my %h = ( (A) => 'twelve', $B => + 'thirteen'); dd \%h;" BEGIN { $^W = 1; } use strict; use Data::Dump; use Const::Fast; use constant ('A', 12); &const(\our $B, 13); my(%h) = (12, 'twelve', $B, 'thirteen'); dd(\%h); -e syntax OK 0:59 >
(AFAICT, this also makes Const::Fast unsuitable in situations where one wants to write code like this:
use constant DEBUG => 0; ... perform_some_debugging_operation() if DEBUG; ...
and have the compiler remove the expensive operation when it sees that DEBUG is false.)
Update: Changed perform_expensive_debugging_operation() to perform_some_debugging_operation(), because, as Eily pointed out in a private message, the cost of the operation is irrelevant if DEBUG (or $DEBUG) is false.
Cheers,
| Athanasius <°(((>< contra mundum | Iustus alius egestas vitae, eros Piratica, |
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Re^3: Using constants as hash keys
by karlgoethebier (Abbot) on Jan 05, 2018 at 15:28 UTC |