Re: store rest of the lines in a array after a matching pattern is found

You don't specifically ask a question, but since you say "rest of the line", I'm guessing your problem is that you're printing too much after "my string".

I'd suggest changing your regular expression to:

if ( $str =~ m/^ServiceCategoryName=(.*)/) {
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which will, if the expression matches, put the rest of the line (i.e., the stuff after the '=') into the $1 capture buffer. From there you could extract the stuff you're interested in, like so:

if ( $str =~ m/^ServiceCategoryName=(.*)/) {
   print $str;

   # Extract the array from "the rest of the line"
   my @array = split /,/, $1;
   print "my string ", $array[0], "\n";
}
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Notes:

You're not providing a format string, so I changed printf to print.
You should use cut & paste to put your actual code, rather than retyping it. That'll help you avoid typos, like the missing comma in your split statement.

...roboticus

When your only tool is a hammer, all problems look like your thumb.

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Re^2: store rest of the lines in a array after a matching pattern is found by Anonymous Monk on May 17, 2018 at 17:35 UTC
Tried that option earlier but got an error Unmatched ( in regex; marked by <-- HERE in m/^ServiceCategoryName=( <-- HERE .*/ at	[reply]
Re^3: store rest of the lines in a array after a matching pattern is found by roboticus (Chancellor) on May 17, 2018 at 17:41 UTC
Then you had a syntax error in your code (such as either missing the closing parenthesis, misplacing it (putting it to the right of the slash), or accidentally escaping it (by preceding it with a \). As you can see here, it should just work: `$ perl foo.pl ServiceCategoryName=foo,bar,baz my string foo $ cat foo.pl use strict; use warnings; my $str = "ServiceCategoryName=foo,bar,baz\n"; if ( $str =~ m/^ServiceCategoryName=(.)/) { print $str; # Extract the array from "the rest of the line" my @array = split /,/, $1; print "my string ", $array[0], "\n"; } else { print "Can't find ServiceCategoryName!\n"; }` [download] ...roboticus When your only tool is a hammer, all problems look like your thumb.*	[reply] [d/l]
Re^3: store rest of the lines in a array after a matching pattern is found by AnomalousMonk (Archbishop) on May 17, 2018 at 19:07 UTC
Tried that option ... You don't say what option you tried (a mortal sin in the Monastery), but one can make a guess at your code: `c:\@Work\Perl\monks>perl -wMstrict -le "my $str = 'ServiceCategoryName=(3,1,0,1,1,0)'; ;; if ($str =~ m/^ServiceCategoryName=(./) { print qq{'$str'}; my @array = split /,/, $str; print qq{first split element: '$array[0]'}; } " Unmatched ( in regex; marked by <-- HERE in m/^ServiceCategoryName=( < +-- HERE ./ at -e line 1.` [download] roboticus has suggested ways to fix this: `c:\@Work\Perl\monks>perl -wMstrict -le "my $str= 'ServiceCategoryName=(3,1,0,1,1,0)'; ;; if ($str =~ m/^ServiceCategoryName=$(.*)$/) { print qq{parenthesized substring: '$1'}; my @array = split /,/, $1; print qq{first split element: '$array[0]'}; } " parenthesized substring: '3,1,0,1,1,0' first split element: '3'` [download] In future, please show exactly what you have tried, the exact output you got, and what you wanted. Please see Short, Self-Contained, Correct Example. Give a man a fish: `<%-{-{-{-<`	[reply] [d/l] [select]