Re^4: Moose 'clone' Constructor

++ Many thanks. That shines a light on all the grey areas, including (from my earlier post):

"XYZ"->$x("fred")
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being exactly equivalent to

$x->("XYZ", "fred")
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— Ken

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Re^5: Moose 'clone' Constructor by tobyink (Canon) on Jul 05, 2018 at 17:11 UTC
Assuming `$x` is a coderef, then yes, they're exactly equivalent. I don't think you can even detect the difference in the Perl OP tree. But if `$x` is a string (containing a method name, optionally qualified with a package name), then `$thing->$x("fred")` will work if `$thing` is a package name (string) or a blessed object, but won't work otherwise. toby döt ink	[reply] [d/l] [select]