Assuming the offending code looks something like this:

my $hashref = { .... };
my $keysCount = keys $hashref;
[download]

Then add a dereference:

my $keysCount = keys ${ $hashref };
[download]

Or just:

my $keysCount = keys $$hashref;
[download]

Thanks...what ended up working was changing:

perl(split/\n/,(keys(${{}))[0])
[download]

to

perl(split/\n/,(keys(%{${{}}))[0])
[download]

Ahem, both of those snippets are non-working:

$ perl -Mstrict -wE 'my $h = {foo=>"bar"}; my $c = keys ${$h};'

Experimental keys on scalar is now forbidden at -e line 1.
Type of arg 1 to keys must be hash or array (not scalar dereference) a
+t -e line 1, near "};"
Execution of -e aborted due to compilation errors.
[download]

$ perl -Mstrict -wE 'my $h = {foo=>"bar"}; my $c = keys $$h;'

Experimental keys on scalar is now forbidden at -e line 1.
Type of arg 1 to keys must be hash or array (not scalar dereference) a
+t -e line 1, near "$h;"
Execution of -e aborted due to compilation errors.
[download]

... presumably you meant:

$ perl -Mstrict -wE 'my $h = {foo=>"bar"}; my $c = keys %{$h};'
[download]

$ perl -Mstrict -wE 'my $h = {foo=>"bar"}; my $c = keys %$h;'
[download]

Aside: how odd that your post continues to garner upvotes (rep up three since I posted this); you don't suppose people vote based on the author's reputation without really reading the post, do you!?



The way forward always starts with a minimal test.

Nevermind, thought this was in reply to my reply.

Ahem, both of those snippets are non-working

And yet, somehow, my post prompted the OP to both find his own solution and post code demonstrating the original problem. Clever huh?

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