in reply to Perl ARRAY() result

In your print statement, $_ is undefined. Therefore, the string "@$_\n" contains only the newline. Your square brackets create a reference to an anonymous array. The text you see is the expected output when you try to print a reference. All you must do is print the variables you want. (You may use the special variable "$," perlvar to format the output.)
} else { # print "@$_\n", [ @$included, $nextValue ] local $, = q(, ); print @$included, $nextValue, "\n" if $currentGoal == $nextValue; return if $nextValue >= $currentGoal; }
Bill