in reply to strptime("%Y-%m") in perl6

choroba has provided a good solution. Depending on what you need exactly, this is another possible solution using a formatter (demonstrated here on the REPL): 
> my $fmt = { sprintf "%04d-%02d", .year, .month };
-> ;; $_? is raw { #`(Block|173600432) ... }
> say Date.new(2019, 1, 1, formatter => $fmt);
2019-01

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Update: Please note that you don't need to predefine the formatter: 
> say Date.new(2019, 1, "1", formatter => { sprintf "%04d-%02d", .year
+, .month })
2019-01

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Replies are listed 'Best First'.
Re^2: strptime("%Y-%m") in perl6
by leszekdubiel (Scribe) on Feb 05, 2019 at 14:01 UTC
    Let's say I want to check if month is valid. In perl 5 it is so simple: 
    
use Time::Piece; localtime()->strptime(@ARGV[0], "%Y-%m");

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    I don't care about date parsing, I don't look at string at all -- perl5 does that for me. 
    
bash$    perl -e 'use Time::Piece; localtime()->strptime(@ARGV[0], "%Y
+-%m"); print "ok\n"; '  "2019-01"
ok


bash$    perl -e 'use Time::Piece; localtime()->strptime(@ARGV[0], "%Y
+-%m"); print "ok\n"; '  "2019-77"
Error parsing time at /usr/lib/x86_64-linux-gnu/perl/5.26/Time/Piece.p
+m line 481.

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    What is elegant way to do thatn in perl6?
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[d/l]
[select]
      But also 
      $ perl -MTime::Piece -le 'localtime()->strptime(shift, "%Y-%m-%d"); pr
+int "ok"'  2019-02-30
ok

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      map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]
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[d/l]
[select]
      Nor sure to really understand your requirement, but what about this: 
      > for <1 5 3 13> -> $month { say Date.new(2019, $month, 1 )}
2019-01-01
2019-05-01
2019-03-01
Month out of range. Is: 13, should be in 1..12
  in block <unit> at <unknown file> line 1

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[d/l]
        I need to check command line args. I expected perl6 to be simple as: 
        
 "parse ARGS[0] as %Y-%m od die"

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        Just one sentence without additional ARGS[0] manipulation.
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[d/l]

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