prob keeping my floats floating

perl-diddler has asked for the wisdom of the Perl Monks concerning the following question:

Having a problem keeping my floating point vars as floats and not being truncated to integers when I try to split the string Lemme show working vs. non:


#working:
>perl -e 'printf "(%s)\n", $ARGV[0]', 2.3
(2.3)

#still good:
> perl -e 'printf "%s\n", do { $ARGV[0] }', 2.3
(2.3)

# now to split 
> perl -we 'printf("(%s)\n", split(q(.), "$ARGV[0]" )  );' 2.3
Missing argument in printf at -e line 1.
()
[download]

Why?

Why missing (argument), and why empty output?
split should output an array in list context and the list length in scalar context, so either a list (array ref, I guess?) of "2, 3" or a scalar '2', as number of elements, no?

What's tripping things up? Ideas?

Comment on prob keeping my floats floating Download Code

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Re: prob keeping my floats floating by pryrt (Abbot) on Feb 15, 2019 at 02:15 UTC
split expects a pattern; `.` is special to a pattern: `C:\Users\Peter>perl -we "print join ':', split('.', '2.3.4')" C:\Users\Peter>perl -we "print join ':', split('\.', '2.3.4')" 2:3:4` [download] addendum: showing number of elements: `C:\Users\Peter>perl -we "print scalar split('.', '2.3.4', -1)" 6 C:\Users\Peter>perl -we "print scalar split('\.', '2.3.4', -1)" 3` [download]	[reply] [d/l] [select]
Re^2: prob keeping my floats floating by perl-diddler (Chaplain) on Feb 15, 2019 at 02:47 UTC
Yeah, I thought I had a backslash before it. I fixed it a different way by changing the 1st arg to an explicit pattern: (this one shows the array ref): `> perl -we ' use P; my @x = split( m{\.}, "$ARGV[0]"); P "\nargv0=%s", "$ARGV[0]"; P "(%s)\n", \@x' "2.3" argv0=2.3 ([2, 3])` [download] Thanks!	[reply] [d/l]