$ref = [ [2, 4], [8, 16] ];
say $ref->[1][1]; #16
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From perldoc perlref

           One more thing here.  The arrow is optional between bracket
+s subscripts, so you can shrink the
           above down to

               $array[$x]{"foo"}[0] = "January";

           Which, in the degenerate case of using only ordinary arrays
+, gives you multidimensional arrays
           just like C's:

               $score[$x][$y][$z] += 42;
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Another way to look at it is to realize that in Perl, different basic types can have the same name. There has to be some way to distinguish between, e.g., a hash and a scalar containing a hash reference. The  -> (arrow) operator (see perlop) makes this syntactic distinction, as it were. Below the top level, nested hashes (and arrays) can only be references, so the compiler does not need an arrow operator for disambiguation (but an  -> can always be used at lower level(s) if you wish).

c:\@Work\Perl\monks>perl -wMstrict -le
"my %hash = ( 'structure' => { 'uses plain sigil'  => 'dereference' } 
+);
 my $hash = { 'reference' => { 'needs -> operator' => 'at top'      } 
+};
 ;;
 print $hash    {'structure'}{'uses plain sigil' };
 print $hash -> {'reference'}{'needs -> operator'};
"
dereference
at top
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Hello Arunkumar_141,

Please read How do I post a question effectively? and change your question accordinly so you can help us help you. :)

Looking forward to your updated version of your question :).