Re^2: local our?

local and our are completely unrelated.

That's not true. local is about aliasing package globals, and our creates a package global in the package where that declaration occurs (and a lexical alias to that in the current scope), so they are related: they both act upon slots in the symbol table of a package. So they are related.

$ perl -E 'package Foo; local our $bar; package main; say for keys %Fo
+o::'
bar
[download]

and

$ perl -E 'our $bar = "foo"; say "1: $bar"; package Foo; { local our $
+bar = "quux"; say "2: $bar"; }; say "3: $bar"; package main; say "4: 
+$bar"; say "Foo::$_" for keys %Foo::'
1: foo
2: quux
3: foo
4: foo
Foo::bar
[download]

perl -le'print map{pack c,($-++?1:13)+ord}split//,ESEL'

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Re^3: local our? by ikegami (Patriarch) on Apr 15, 2019 at 01:05 UTC
The fact that they both can take a package variables as an argument doesn't make them related in any meaningful way. local is about aliasing package globals No. For example, `my %h; local $h{x};`. It's about making temporary backups of some values. our creates a package global No. `our` creates a lexical variable (that's aliased to the specified package variable). Simply mentioning the package var is what creates it. `$ perl -le' print $::{var} // "[undef]"' [undef] $ perl -le'$var; print $::{var} // "[undef]"' *main::var` [download]	[reply] [d/l] [select]
Re^3: local our? by LanX (Saint) on Apr 14, 2019 at 21:15 UTC
I think it's important to stay accurate: > our creates a package global in the package where that declaration occurs our will create a new STASH entry only, iff it doesn't already exist and it will not touch the value. > local is about aliasing package globals I can't see any "aliasing" process here, it's still the same underlying package variable. what do you call an "alias" here when doing `local $main::bob;` ? Cheers Rolf _{(addicted to the Perl Programming Language :) Wikisyntax for the Monastery FootballPerl is like chess, only without the dice}	[reply] [d/l]