in reply to Finding missing elements in a sequence (code)
Since the value of the array index is not accessible in a simple for loop, I set the values of the array equal to the index and inverted the sense of the final grep, but otherwise everything is as it was. Note that this code will fail (just like the original one) if 0 is contained in the interval $low .. $high. But this can easily be fixed by setting the values we found to undef rather than 0 and checking for defined values in the final grep...sub find_holes { my @list = @{ shift() }; @list = sort { $a <=> $b } @list; my $low = $list[0]; my $high = $list[-1]; my @notfound; @notfound[$low..$high] = ($low..$high); $notfound[$_] = 0 for @list; my @vacancies = grep {$_} @notfound; return \@vacancies; }
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