Re: bigint - float?

If I understand your problem, then this works with the newest version of Math::BigInt. I'm fairly certain that it won't work with some earlier versions. I seem to remember having trouble with this sort of thing in the past.

$x = Math::BigInt->bstr( $bigint );
$bits = int( log( $x ) / log( 2 ) ) + 1;
[download]

___________________
Kurt

Comment on Re: bigint - float? Download Code

Replies are listed 'Best First'.
length * 3.3219 by jhanna (Scribe) on Nov 23, 2001 at 21:38 UTC
I'm using whatever BigInt came with ActivePerl... It's likely not the latest. It does occur to me that I can probably do something like: $bits=int((length($bigint)-1) * 3.3219)+1; where 3.3219 is log(10)/log(2) and the length of $bigint is relatively large assuming that length($bigint) returns the length of the string / ie number of decimals. It also occurred to me that I could do a manual conversion to float by something like this: $float=substr($bigint,1,1).'.'.substr($bigint,2).'e'.(length($bigint)-2); where the point is to create a float string value out of the bigint string value... Either of these might work, but they're a bit ugly... j	[reply]
Re: length * 3.3219 by sifukurt (Hermit) on Nov 23, 2001 at 22:34 UTC
As long as you have a fairly recent ActivePerl, you should be ok. I think only relatively old versions of Math::BigInt did weird things sometimes with `bstr()`. The newest version of Math::BigInt installs like a charm on a Win32 system, btw. So either way, you might be better off installing the newest version. ___________________ Kurt	[reply] [d/l]