Reference on calling to a function

hotshot has asked for the wisdom of the Perl Monks concerning the following question:

hello dear brothers !

I have a function that gets a reference to an array:

sub myfunc {

   my $arrRef = shift;
   # do my stuff here
}
[download]

and I have a scalar that I wonna send this function. Is there a short way of doing that without having to define a new array variable as the followings:

my @arr = ($var);
&myfunc(\@arr);
[download]

btw, I'v tried the followings and it doesn't work:

&myfunc(\($var));
[download]

Hotshot

Comment on Reference on calling to a function Select or Download Code

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(jeffa) Re: Reference on calling to a function by jeffa (Bishop) on Dec 02, 2001 at 21:51 UTC
How about: `&myfunc([$var]);` [download] jeffa L-LL-L--L-LL-L--L-LL-L-- -R--R-RR-R--R-RR-R--R-RR F--F--F--F--F--F--F--F-- (the triplet paradiddle)	[reply] [d/l]
(ar0n) Re: (jeffa) Re: Reference on calling to a function by ar0n (Priest) on Dec 02, 2001 at 23:10 UTC
And what that does is create an anonymous array from the list between the brackets and return a reference to it. So: `my @array = qw/1 2 3 4/; myfunc( \@array );` [download] and `myfunc( [ qw/1 2 3 4/ ] );` [download] are functionally equivalent. [ ar0n -- want job (boston) ]	[reply] [d/l] [select]
(podmaster) Re: Reference on calling to a function by PodMaster (Abbot) on Dec 03, 2001 at 05:08 UTC
What you say? You haven't (speculation) read perlref or perldata? Well you better go read it now, because it is where the knowledge you seek is contained.	[reply]