So, the ';' is being used as the delimiter for q...

q;}continue ... $!\n);
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Very strange indeed, I thought the closing bracket was the delimiter and thus was quite confused. So, not only does it physically wrap your code in a while loop, it adds an unnecessary semicolon before the end of the block. Or at least thats what it looks like to me....

Oh, in last Friday's golf, chipmunk had a one-liner entry that (ab)used this "physical" wrapping feature of -p (well -n really) for those that want another data point to play with.

-Blake