Re: subroutine within regex quantifier?

There's the experimental (?{...}) construct, but I can't think of a way to use that. Why not use length and a slightly different regex?

while (length($target_letters) != WORD_LENGTH &&
    $target_letters =~ /[^A-Za-z]/) {
    # prompt
}
[download]

Seems clearer to me, as well as *possible*.

Comment on Re: subroutine within regex quantifier? Download Code

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Re: Re: subroutine within regex quantifier? by hagen (Friar) on Dec 04, 2001 at 10:26 UTC
Thanks chromatic, that is clearer and `feels' more Perl-like. I got fixated on having to use the quantifier. . I also appreciate dws's suggestion re compiling only once. Thanks for the prompt responses hagen 8-)	[reply]