in reply to Re: Re: List::Ranking
in thread List::Ranking
Right. So instead, try this:
my %data = ( 'slashdot.org' => 180, 'cpan.org' => 150, 'perl.com' => 150, 'apache.org' => 120, ); my @keys = keys %data; # invert the %data hash, creating arrayrefs each with list # of elements with the same ranking my %ranks; push @{$ranks{$data{$_}}}, $_ for @keys; # count/sort the rankings my @ranks = reverse sort {$a<=>$b} keys %ranks; for my $rank ( 0 .. $#ranks ) { # print them my @tied = @{$ranks{ $ranks[$rank] }}; if (@tied > 1) { # more than one with this ranking local $"=', '; my $last = pop @tied; print "@tied and $last all have rank ". 1+$ranks[$rank] ."\n"; } else { print "@tied has rank ". 1+$ranks[$rank] ."\n"; } }
Update: Rankings should be 1-based.
dmm
You can give a man a fish and feed him for a day ...
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