in reply to Sub prototypes...
Executes like this:try { die "foobar\n"; print "OK"; } catch { print "FAILED!\n"; };
In other words, there are two arguments to try(): a coderef and whatever catch() returns (normally a coderef, its own first argument). So catch() has to be called before try() can be called.try( sub { die "Foobar"; print "OK"; }, catch(sub { print "FAILED!\n"; }) );
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