Re: Obtaining a return code

The special variable $? holds the status of the backtick or system operation. If you're really curious, you can do: my $sig_number = ($? & 255); to see which signal killed the process, if any. It's not all that useful, though, for system(), as you can get the return value anyway (as turnstep points out below).

Which return code are you expecting?

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RE: Answer: Obtaining a return code by turnstep (Parson) on May 21, 2000 at 20:36 UTC
But $? is the same thing as just reading the return value yourself, right? At any rate, $? on my Win32 system doesn't show anything except "0", no matter what is in the system call: `$rv = system("uname"); print "Returned a $rv and \$? is $?\n"; $rv = system("ver"); print "Returned a $rv and \$? is $?\n";` [download] Unix produces: SunOS Returned a 0 and $? is 0 Returned a 65280 and $? is 65280 Windoze produces: Bad command or file name Returned a 0 and $? is 0 Windows 98 [Version 4.10.1998] Returned a 0 and $? is 0	[reply] [d/l]

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RE: Answer: Obtaining a return code
by turnstep (Parson) on May 21, 2000 at 20:36 UTC

$rv = system("uname");
print "Returned a $rv and \$? is $?\n";
$rv = system("ver");
print "Returned a $rv and \$? is $?\n";
[download]

Unix produces:

SunOS
Returned a 0 and $? is 0
Returned a 65280 and $? is 65280

Windoze produces:

Bad command or file name
Returned a 0 and $? is 0

Windows 98 [Version 4.10.1998]

Returned a 0 and $? is 0

[reply]
[d/l]