in reply to Bizarre References Question
Problem goes away... Dunno about your situation tho'.my $x=\do{my $x="string"};
Update it appears Zaxo has worked this out, but the above code is a viable workaround. Better imo than ($value)=($$value) if only because the resultant can be assigned to.
Yves / DeMerphq
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When to use Prototypes?
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