Ok not at all good but (in my eyes at least) funny. 
#!/usr/bin/perl -w
use strict;

open(F,$0);$_=<F>;chomp;$_.=<F>;
s;^.*?\/(..).*?i(.).(.*?)\s.*?\ss(.)(.).(.).*;
J$1$4 a$2o$4he$5 $3 ha$6ke$5!;;
print;

[download]
See if you can guess what the c stands for in cjaph.

Darkling.
Think.

Replies are listed 'Best First'.
Re: cjaph - SOLUTION
by domm (Chaplain) on Mar 04, 2002 at 20:20 UTC
    You open the script itself (location stored in $0) on filehandle F and assign the first two lines to $_.

    Then you start a substitution operating on $_, with ; as a delimiter, so de-obfuscated (using a | as delimiter) it looks like: 

    $_=~s|^.*?\/(..).*?i(.).(.*?)\s.*?\ss(.)(.).(.).*|J$1$4 a$2o$4he$5 $3 
+ha$6ke$5!|;

    [download]
    You basically scan the first two lines for some stuff:
    1. The two chars following the first slash go into $1 ('us') 
      #!/usr/bin/perl -w
use strict;
    2. Then you scan for the next 'i' and save the following char in $2 ('n') 
      #!/usr/bin/perl -w
use strict;
    3. You skip the next char and save everything up to the next space in $3 ('perl') 
      #!/usr/bin/perl -w
use strict;
    4. You skip to the next space followed by 's' and save the next char in $4 ('t') 
      #!/usr/bin/perl -w
use strict;
    5. The next char goes into $5 ('r') 
      #!/usr/bin/perl -w
use strict;
    6. Then skip one and save the last in $6 ('c') 
      #!/usr/bin/perl -w
use strict;
    and then print the new value of $_.

    But I still don't know what the c in cjaph stands for ...

[reply]
[d/l]
      Ok. Just to stop everyone from guessing (because I know you've all been worrying about it for days now!) the "c" in cjaph, as is quite obvious from the nature of the japh, stands for "crap".

      Darkling.
      Think.
[reply]

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