⭐ in reply to Is it possible to do pass by reference in Perl?
@_ holds the arguments passed to a subroutine, and it is common idiom to see something like:
Why is that? Why don't we just use the @_ array directly?sub mySub{ my $Arg = shift; } sub mySub2{ my ($Arg) = @_; }
First, there is the laudable goal of more readable code, which is sufficient reason, in itself, to rename variables away from cryptic things like $_[3]. But really, we copy values out of @_ because (from the man page) "its elements are aliases for the actual scalar parameters."
In short, this means that if you modify an element of @_ in your subroutine, you are also modifying the original argument. This is almost never the expected behavior! Further, if the argument is not updatable (like a literal value, or a constant), your program will die with an error like "Modification of a read-only value attempted."
Consider:
will print out:sub test{ $_[0] = 'New Value'; } my $Var = 'Hi there'; print "$Var\n"; test ($Var); print "$Var\n";
So, yes, you can do pass-by-reference in Perl, even without backslashes; but it is almost always better (some would leave out the "almost" in this statement) to make your caller explicitly pass you a reference if you intend to modify a value.Hi there New Value
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